I’ve said before, and no doubt will say again, that one of my favorite things about this blog is how much I learn from your feedback and the demo files you send me.
Recently I received a file from Otmar Kramnis of the Hochschule Luzern demonstrating the fastest SQL-based method I have yet seen to solve the challenge we looked at in part 1 and in part 2, and with a few minor modifications, this is the demo we’re going to focus on today: Outer Join Demo 7
As you may recall, the aim is to show a week’s worth of daily sales totals for all employees whether they had any sales or not.
Or, to restate the problem in more generic terms: we need to show all values from table A, whether or not there are any matching values in table B. This is known as an “outer join”, or more precisely a “left outer join”, since we want to see all values in the “left” table (Employees), whether or not they have corresponding matches in the “right” table (Sales).
